7.10. Exercises — How to Think like a Computer Scientist: Interactive Edition

What do these expressions evaluate to?
1. 3 == 3
2. 3 != 3
3. 3 >= 4
4. not (3 < 4)
1. True
2. False
3. False
4. False
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Give the logical opposites of these conditions. You are not allowed to use the not operator.
1. a > b
2. a >= b
3. a >= 18 and day == 3
4. a >= 18 or day != 3

Write a function which is given an exam mark, and it returns a string — the grade for that mark — according to this scheme:

Mark Grade

>= 90 A

[80-90) B

[70-80) C

[60-70) D

< 60 F

The square and round brackets denote closed and open intervals. A closed interval includes the number, and open interval excludes it. So 79.99999 gets grade C , but 80 gets grade B.

Test your function by printing the mark and the grade for a number of different marks.
def getGrade(grade): #your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(getGrade(95),'A','Tested getGrade on input of 95') self.assertEqual(getGrade(85),'B','Tested getGrade on input of 85') self.assertEqual(getGrade(65),'D','Tested getGrade on input of 65') self.assertEqual(getGrade(79.99999),'C','Tested getGrade on input of 79.9999') self.assertEqual(getGrade(80),'B','Tested getGrade on input of 80') myTests().main()
def grade(mark): if mark >= 90: return "A" else: if mark >= 80: return "B" else: if mark >= 70: return "C" else: if mark >= 60: return "D" else: return "F" mark = 83 print( "Mark:", str(mark), "Grade:", grade(mark))
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Mark	Grade
>= 90	A
[80-90)	B
[70-80)	C
[60-70)	D
< 60	F

Modify the turtle bar chart program from the previous chapter so that the bar for any value of 200 or more is filled with red, values between [100 and 200) are filled yellow, and bars representing values less than 100 are filled green.

In the turtle bar chart program, what do you expect to happen if one or more of the data values in the list is negative? Go back and try it out. Change the program so that when it prints the text value for the negative bars, it puts the text above the base of the bar (on the 0 axis).

import turtle def drawBar(t, height): """ Get turtle t to draw one bar, of height. """ t.begin_fill() # start filling this shape if height < 0: t.write(str(height)) t.left(90) t.forward(height) if height >= 0: t.write(str(height)) t.right(90) t.forward(40) t.right(90) t.forward(height) t.left(90) t.end_fill() # stop filling this shape xs = [48, -50, 200, 240, 160, 260, 220] # here is the data maxheight = max(xs) minheight = min(xs) numbars = len(xs) border = 10 tess = turtle.Turtle() # create tess and set some attributes tess.color("blue") tess.fillcolor("red") tess.pensize(3) wn = turtle.Screen() # Set up the window and its attributes wn.bgcolor("lightgreen") if minheight > 0: lly = 0 else: lly = minheight - border wn.setworldcoordinates(0-border, lly, 40*numbars+border, maxheight+border) for a in xs: drawBar(tess, a) wn.exitonclick()
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Write a function findHypot. The function will be given the length of two sides of a right-angled triangle and it should return the length of the hypotenuse. (Hint: x ** 0.5 will return the square root, or use sqrt from the math module)
def findHypot(a,b): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(findHypot(12.0,5.0),13.0,"Tested findHypot on inputs of 12.0 and 5.0") self.assertEqual(findHypot(14.0,48.0),50.0,"Tested findHypot on inputs of 14.0 and 48.0") self.assertEqual(findHypot(21.0,72.0),75.0,"Tested findHypot on inputs of 21.0 and 72.0") self.assertAlmostEqual(findHypot(1,1.73205),1.999999,2,"Tested findHypot on inputs of 1 and 1.73205") myTests().main()

Write a function called is_even(n) that takes an integer as an argument and returns True if the argument is an even number and False if it is odd.
def is_even(n): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(is_even(10),True,"Tested is_even on input of 10") self.assertEqual(is_even(5),False,"Tested is_even on input of 5") self.assertEqual(is_even(1),False,"Tested is_even on input of 1") self.assertEqual(is_even(0),True,"Tested is_even on input of 0") myTests().main()
from test import testEqual def is_even(n): if n % 2 == 0: return True else: return False testEqual(is_even(10), True) testEqual(is_even(5), False) testEqual(is_even(1), False) testEqual(is_even(0), True)
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Now write the function is_odd(n) that returns True when n is odd and False otherwise.
def is_odd(n): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(is_odd(10),False,"Tested is_odd on input of 10") self.assertEqual(is_odd(5),True,"Tested is_odd on input of 5") self.assertEqual(is_odd(1),True,"Tested is_odd on input of 1") self.assertEqual(is_odd(0),False,"Tested is_odd on input of 0") myTests().main()

Modify is_odd so that it uses a call to is_even to determine if its argument is an odd integer.
def is_odd(n): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(is_odd(10),False,"Tested is_odd on input of 10") self.assertEqual(is_odd(5),True,"Tested is_odd on input of 5") self.assertEqual(is_odd(1),True,"Tested is_odd on input of 1") self.assertEqual(is_odd(0),False,"Tested is_odd on input of 0") myTests().main()
from test import testEqual def is_even(n): if n % 2 == 0: return True else: return False def is_odd(n): if is_even(n): return False else: return True testEqual(is_odd(10), False) testEqual(is_odd(5), True) testEqual(is_odd(1), True) testEqual(is_odd(0), False)
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Write a function is_rightangled which, given the length of three sides of a triangle, will determine whether the triangle is right-angled. Assume that the third argument to the function is always the longest side. It will return True if the triangle is right-angled, or False otherwise.

Hint: floating point arithmetic is not always exactly accurate, so it is not safe to test floating point numbers for equality. If a good programmer wants to know whether x is equal or close enough to y, they would probably code it up as
```
if  abs(x - y) < 0.001:      # if x is approximately equal to y
    ...
```
def is_rightangled(a, b, c): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(is_rightangled(1.5,2.0,2.5),True,"Tested is_rightangled on inputs of 1.5, 2.0 and 2.5") self.assertEqual(is_rightangled(4.0,8.0,16.0),False,"Tested is_rightangled on inputs of 4.0, 8.0 and 16.0") self.assertEqual(is_rightangled(4.1,8.2,9.1678787077),True,"Tested is_rightangled on inputs of 4.1, 8.2 and 9.1678787077") self.assertEqual(is_rightangled(4.1,8.2,9.16787),True,"Tested is_rightangled on inputs of 4.1, 8.2, and 9.16787") self.assertEqual(is_rightangled(4.1,8.2,9.168),False,"Tested is_rightangled on inputs of 4.1, 8.2 and 9.168") self.assertEqual(is_rightangled(0.5,0.4,0.64031),True,"Tested is_rightangled on inputs of 0.5, 0.4 and 0.64031") myTests().main()

Extend the above program so that the sides can be given to the function in any order.
def is_rightangled(a, b, c): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(is_rightangled(1.5,2.5,2.0),True,"Tested is_rightangled on inputs of 1.5, 2.5 and 2.0") self.assertEqual(is_rightangled(16.0,4.0,8.0),False,"Tested is_rightangled on inputs of 16.0, 4.0 and 8.0") self.assertEqual(is_rightangled(4.1,8.2,9.1678787077),True,"Tested is_rightangled on inputs of 4.1, 8.2 and 9.1678787077") self.assertEqual(is_rightangled(4.1,9.16787,8.2),True,"Tested is_rightangled on inputs of 4.1, 9.16787 and 8.2") self.assertEqual(is_rightangled(4.1,8.2,9.168),False,"Tested is_rightangled on inputs of 4.1, 8.2 and 9.168") self.assertEqual(is_rightangled(0.5,0.64031,0.4),True,"Tested is_rightangled on inputs of 0.5, 0.64031 and 0.4") myTests().main()
from test import testEqual def is_rightangled(a, b, c): is_rightangled = False if a > b and a > c: is_rightangled = abs(b**2 + c**2 - a**2) < 0.001 elif b > a and b > c: is_rightangled = abs(a**2 + c**2 - b**2) < 0.001 else: is_rightangled = abs(a**2 + b**2 - c**2) < 0.001 return is_rightangled testEqual(is_rightangled(1.5, 2.0, 2.5), True) testEqual(is_rightangled(4.0, 8.0, 16.0), False) testEqual(is_rightangled(4.1, 8.2, 9.1678787077), True) testEqual(is_rightangled(4.1, 8.2, 9.16787), True) testEqual(is_rightangled(4.1, 8.2, 9.168), False) testEqual(is_rightangled(0.5, 0.4, 0.64031), True)
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A year is a leap year if it is divisible by 4 unless it is a century that is not divisible by 400. Write a function that takes a year as a parameter and returns True if the year is a leap year, False otherwise.
def isLeap(year): # your code here ==== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(isLeap(1944),True,"Tested isLeap on an input of 1944") self.assertEqual(isLeap(2011),False,"Tested isLeap on an input of 2011") self.assertEqual(isLeap(1986),False,"Tested isLeap on an input of 1986") self.assertEqual(isLeap(1800),False,"Tested isLeap on an input of 1800") self.assertEqual(isLeap(1900),False,"Tested isLeap on an input of 1900") self.assertEqual(isLeap(2000),True,"Tested isLeap on an input of 2000") self.assertEqual(isLeap(2056),True,"Tested isLeap on an input of 2056") myTests().main()

Implement the calculator for the date of Easter.

The following algorithm computes the date for Easter Sunday for any year between 1900 to 2099.

Ask the user to enter a year. Compute the following:
a = year % 19

b = year % 4

c = year % 7

d = (19 * a + 24) % 30

e = (2 * b + 4 * c + 6 * d + 5) % 7

dateofeaster = 22 + d + e
Special note: The algorithm can give a date in April. Also, if the year is one of four special years (1954, 1981, 2049, or 2076) then subtract 7 from the date.

Your program should print an error message if the user provides a date that is out of range.
year = int(input("Please enter a year")) if year >= 1900 and year <= 2099: a = year % 19 b = year % 4 c = year % 7 d = (19*a + 24) % 30 e = (2*b + 4*c + 6*d + 5) % 7 dateofeaster = 22 + d + e if year == 1954 or year == 2981 or year == 2049 or year == 2076: dateofeaster = dateofeaster - 7 if dateofeaster > 31: print("April", dateofeaster - 31) else: print("March", dateofeaster) else: print("ERROR...year out of range")
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7.10. Exercises¶